Wednesday, November 18, 2009

Two-column problem

It was not possible to put through scanner to post my problem on Blog. I am very sorry about that inconvenience.
So the two- column problem is to provide a number choice for the player to win 31 as a total from both players' choices.
So for player 1, 1+2+3+4+5 = 15 and he starts at 1. and take one more round to get another 15 and ends at 1. His toatl is 31. So for the first player the best choice is 1. And
for 2nd player the choice left is to start at 2
and his toatl is 2+3+4+5= 14 and aother round is 14 and it becomes =28 and he will add 3 or 2 in his tatal the he will get either 1 less or = 31. And his choice seems also sustainable.
Now if he starts at 3 then 3+4+5 =then again he will get 3 less or 2 more in his choice.
So by looking at the problem we can see the try and guess straegy may work if your guess works well for the first time and you want to try another different number also.

3 comments:

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  2. I never thought about the approach of adding up all 5 numbers getting to be 15. I'm still not too clear on how this helps you choose the best number to start off with, nor do I quite understand the strategy yet. However, it was definitely a different approach than what I took, so it was interesting to compare! Very creative Darshan.

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  3. Interesting! both you and Prem had a very similar way of solving this problem. Adding the numbers up to 15 and then deducing that if these numbers were used twice the best number to start off with is 1. Very different from the way I looked at it!

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